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Monday, October 26, 2015

Inequality from UW challenge of the week [Solution]

The problem was here.

In brief

xi are n real numbers such that

nk=1xi=0


nk=1x2i=1


Show that for some i,j,

xixj1n


Solution


The official solution is quite neat.

wlog, assume x1x2xn.

Now

0nk=1(xkx1)(xnxk)=nx1xn1


(The equality is just gotten from expanding out and using the given identities).

The inequality now follows immediately.

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