$P$ is a polynomial with integer coefficients. Show that if $a$ is an integer such that
$$ P(P(P(a))) = a$$
then
$$ P(a) = a$$
Solution Sketch:
This uses the fact that $P(x) - P(y)$ is divisible by $x - y$ to get a cyclic chain of divisibility conditions implying each one in the chain is $\pm1$ times the others. Some assumptions like $P(a) \gt a$ etc lead to contradictions.
$$ P(P(P(a))) = a$$
then
$$ P(a) = a$$
Solution Sketch:
This uses the fact that $P(x) - P(y)$ is divisible by $x - y$ to get a cyclic chain of divisibility conditions implying each one in the chain is $\pm1$ times the others. Some assumptions like $P(a) \gt a$ etc lead to contradictions.
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