Another interesting property of unit fractions (numbers of the form 1n for positive integer n).
Part A)
Suppose f:[0,1]→R is any continuous function such that f(0)=f(1).
Show that for every natural number n>0, there is some c∈[0,1] (c dependent on n and f) such that f(c)=f(c+1n)
Basically the graph of f has a chord of length 1n.
Part B)
Suppose r∈(0,1) is a real number such that r is not a unit fraction.
Show that there is some continuous function fr (dependent on r) such that
fr:[0,1]→R, fr(0)=fr(1) and for any c∈[0,1−r], fr(c)≠fr(c+r).
i.e the graph of fr has no chord of length r.
[Solution]
Part A)
Suppose f:[0,1]→R is any continuous function such that f(0)=f(1).
Show that for every natural number n>0, there is some c∈[0,1] (c dependent on n and f) such that f(c)=f(c+1n)
Basically the graph of f has a chord of length 1n.
Part B)
Suppose r∈(0,1) is a real number such that r is not a unit fraction.
Show that there is some continuous function fr (dependent on r) such that
fr:[0,1]→R, fr(0)=fr(1) and for any c∈[0,1−r], fr(c)≠fr(c+r).
i.e the graph of fr has no chord of length r.
[Solution]
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