The puzzle was to compute
∫1+x2(1−x2)√1+x4dx
Solution
As usual, a clever substitution needs to be sought.
In this case, you divide the numerator and denominator by x2 and then make the substitution t=x−1x.
This results in
−∫dtt√t2+1
which is a standard integral.
∫1+x2(1−x2)√1+x4dx
Solution
As usual, a clever substitution needs to be sought.
In this case, you divide the numerator and denominator by x2 and then make the substitution t=x−1x.
This results in
−∫dtt√t2+1
which is a standard integral.
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